Appendix 3- Example Using Figures for a Passenger Ship
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Statutory Documents - IMO Publications and Documents - Resolutions - Maritime Safety Committee - Resolution MSC.362(92) – Revised Recommendation on a Standard Method for Evaluating Cross-Flooding Arrangements – (Adopted on 14 June 2013) - Appendix 3- Example Using Figures for a Passenger Ship

Appendix 3- Example Using Figures for a Passenger Ship

  Dimension of the considered cross-flooding pipe:

Diameter D = 0.39 m
Length l = 21.0 m
Cross-section area S = 0.12 m2
Wall thickness t = 17.5 mm

  k-values for the considered cross-flooding system:

Inlet 0.45
Pipe friction 1.08
2 radius bends (α = 45°) 0.36
Non-return valve 0.50

 Sufficient air venting is assumed to be in place.

 From this follows:

 Time required from commencement of cross flooding θ 0 to the final equilibrium condition θf :

 Head of water before commencement of cross-flooding:

H 0 = 5.3m

 Volume of water which is used to bring the ship from commencement of cross-flooding to the final equilibrium condition:

Wf = 365m 3

 Final head of water after cross-flooding:

 Calculation of any transient situation of cross-flooding:

 The purpose is to find the situation after 600s.

 Assumed transient situation:

  • Cross-flooded volume: 265 m3

 Volume of water which is used to bring the vessel from the transient situation to the final equilibrium : Wθ = 365 m3 – 265 m3 = 100 m3

  • Corresponding head of water: Hθ = 2.8 m

 Time required to bring the vessel from any transient situation to the final equilibrium condition:

  Tθ = 240 s

 Time between commencement of cross-flooding and assumed transient situation:

 T = Tf – Tθ = 721 s – 240 s = 481 s

 As T is less than 600 s, further transient situations with larger cross-flooded volume may be calculated in the same way.

 On the reverse, if T was of more than 600 s, further transient situation with smaller cross-flooded volume may be calculated.

 Situation after 600 s may be found by successive iterations.


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