Footnote
Clasification Society 2024 - Version 9.40

Footnote

Parent topic: Footnotes
Calculation of ingredients of Test Fluid “C” (Example: 2m3/h Bilge Separator). Operating period for the Test with Test Fluid “C” as per 1.2.11: 2.5 hours plus conditioning time (say 0.5hour) = 3 hours
Net volume needed for the Test: Volume of test water: 2m3x 3 hours = 6m3
  Volume Test Fluid “C”: 6% of test water = 0.06 x 6m3 = 0.36m3
Actual Volume to be prepared:
  Volume of Test Fluid “C” to be prepared: 1.2 times of the net volume of Test Fluid “C” = 1.2 x 0.36 = 0.432m3
  Volume of fresh water in Test Fluid “C”: (947.8g/1000g) of Test Fluid “C” = 0.9478 x 0.432 = 0.4094m3
  Weight of Test Fluid “A”: (25g/1000g) of Test Fluid “C” = 25/1000 x 0.432 x 1000 = 10.8kg
  Weight of Test Fluid “B”: (25g/1000g) of Test Fluid “C” = 25/1000 x 0.432 x 1000 = 10.8kg
  Weight of surfactant: (0.5g/1000g) of Test Fluid “C” = 0.5/1000 x 0.432 x 1000 = 0.216kg
  Weight of iron oxide: (1.7g/1000g) of Test Fluid “C”) = 1.7/1000 x 0.432 x 1000 x 0.734kg
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