Appendix 4 - Examples of Determination of Pollution Categories for Mixtures

This section presents a number of examples to illustrate how pollution categories are derived for mixtures, based on the procedures identified in this document. Please note that only parts GESAMP hazard profiles have been presented for the purposes of the examples. It should, however, be noted that a value for each rating would normally be included in a complete GESAMP hazard profile.

Methodology

Step 1	Determine for each component the applicable row in table 1, by means of its hazard profile, taken from the GESAMP Composite list. This will determine the component factor. Test the rows in descending order and find the first combination of ratings that is consistent with the GESAMP hazard profile.
Step 2	Multiply the component factor with the percentage of the component in the mixture. This will result in the value Sp.
Step 3	Add all resultant Sp values and determine the pollution category.

Example 1

Steps 1 and 2

The amount of component 1 in the mixture is 11%. Its GESAMP hazard profile (GHP), taken from the GESAMP Composite list is:

A1	A2	B1	B2	D3	E2
4	NR	6

The next step is to consult table 1. The GHP corresponds to row a in table 1.

The component factor is 100,000. The multiple is therefore 1,100,000.

(i.e. 11 % by wt x 100,000 = 1,100,000)

The amount of component 2 is 67% of the mixture. Its GESAMP hazard profile, taken from the GESAMP Composite list is:

A1	A2	B1	B2	D3	E2
4	NR	1	1

The GHP corresponds to row q in table 1. The component factor is 1; the multiple is 67.

The amount of component 3 in the mixture is 22%. Its GESAMP hazard profile, taken from the GESAMP Composite list is:

A1		A2	B1	B2	D3	E2
		R	3

This GHP corresponds to row o in table 1. The component factor is 10; the multiple is 220.

Step 3

Component number	Applicable Row Table 1	Component Factor (Cp)	% in mixture	Multiple (Cp x %)
1	a	100,000	11	1,100,000
2	q	1	67	67
3	o	10	22	220
Sp				1,100,287

Sp = multiple 1 + multiple 2 + multiple 3 = 1,100,287

Referring to table 2, identify the row corresponding to the calculated Sp value.

The Sp ≥ 25,000, the mixture is therefore Pollution Category X.

Example 2

Steps 1 and 2

The amount of component 1 is 11% of the mixture, its GESAMP hazard profile, taken from the GESAMP/EHS Composite list is:

A1	A2	B1	B2	D3	E2
		5		C

The GHP corresponds to row i in table 1. The component factor is therefore 1,000 and the multiple is 11,000.

The amount of component 2 is 67 % of the mixture, its GESAMP hazard profile, taken from the GESAMP/EHS Composite list is:

A1	A2	B1	B2	D3	E2
4	NR		1

This GHP corresponds to row q in table 1.The corresponding component factor is 1 and the multiple is 67.

The amount of component 3 is 22% of the mixture, its GESAMP hazard profile, taken from the GESAMP/EHS Composite list is:

A1	A2	B1	B2	D3	E2
		3

This corresponds to row o in table 1. The corresponding component factor is 10 and the multiple is 220.

Step 3

Component number	Applicable Row Table 1	Component Factor (Cp)	% in mixture	Multiple (Cp x %)
1	i	1,000	11	11,000
2	q	1	67	67
3	o	10	22	220
Sp				11,287

Sp = 11,287

Referring to table 2, Sp < 25,000 and Sp ≥ 25, the mixture is therefore pollution category Y.

Example 3

Steps 1 and 2

The amount of component 1 is 2% of the mixture, its GESAMP Hazard profile, taken from the GESAMP Composite list is:

A1	A2	B1	B2	D3	E2
		3

The GHP corresponds to row o in table 1. The component factor is 10; the multiple is 20.

The amount of component 2 is 4% of the mixture, its GESAMP Hazard profile, taken from the GESAMP Composite list is completely blank.

A1	A2	B1	B2	D3	E2
4	NR		1

The GHP corresponds to row q in table 1. The component factor is 1; the multiple is 4.

The amount of component 3 is 94% of the mixture, its GESAMP Hazard profile, taken from the GESAMP Composite list is completely blank.

A1	A2	B1	B2	D3	E2

The GHP corresponds to row u in table 1. The component factor is 0; the multiple is 0.

All components are OS, which corresponds to row u in table 1. The component factors and multiples are both 0.

Step 3

Component number	Applicable Row Table 1	Component Factor (Cp)	% in mixture	Multiple (Cp x % )
1	o	10	2	20
2	q	1	4	4
3	u	0	94	0
Sp				24

Sp = 24

Referring to table 2, Sp < 25 and not all components are OS therefore pollution category Y.

Example 4

Steps 1 and 2

The amount of component 1 is 20% of the mixture, its GESAMP Hazard profile, taken from the GESAMP Composite list is completely blank or zero.

A1	A2	B1	B2	D3	E2
		0

Component 2 is 80% of the mixture, its GESAMP Hazard profile, taken from the GESAMP Composite list is completely blank.

A1	A2	B1	B2	D3	E2

All components are OS, which corresponds to row u in table 1. The component factors and multiples are both 0.

Step 3

Component number	Applicable Row Table 1	Component Factor (Cp)	% in mixture	Multiple (Cp x % )
1	u	0	20	0
2	u	0	80	0
Sp				0

Sp = 0

Referring to table 2, a mixture where all individual components are OS, therefore the mixture is OS.

Example 5

Steps 1 and 2

The amount of component 1 is 70% of the mixture, its GESAMP hazard profile, taken from the GESAMP Composite list is:

A1	A2	B1	B2	D3	E2
		4

This corresponds to row m in table 1. The component factor is 100 and the multiple is 7,000.

The amount of component 2 is 29% of the mixture.

It is a diluent mineral oil so there is no applicable row in table 1.

The component factor assigned to diluent mineral oil is 100 (see paragraph 5.4) and the multiple is 2,900.

The amount of component 3 is 1% of the mixture.

It is an unassessed component, so there is no applicable row in table 1.

Given the component is 1% of the mixture, the component factor is 10,000 (see paragraph 5.4) and the multiple is therefore 10,000.

Step 3

Component number	Applicable Row Table 1	Component Factor (Cp)	% in mixture	Multiple (Cp x % )
1	m	100	70	7000
2	Component is diluent mineral oil	100	29	2,900
3	Unassessed component	10,000	1	10,000
Sp				19,900

Sp = 19,900

Referring to table 2, Sp < 25,000 and Sp ≥ 25. The mixture is therefore pollution category Y.

Example 6

Steps 1 and 2

The amount of component 1 is 2% of the mixture, its GESAMP Hazard profile, taken from the GESAMP Composite list is:

A1	A2	B1	B2	D3	E2
5	NR			M

This corresponds to row d in table 1. The component factor is 25,000 and the multiple is 50,000.

Component 2 is 98 % of the mixture, its GESAMP Hazard profile, taken from the GESAMP Composite list is:

A1	A2	B1	B2	D3	E2
			≥ 1

This corresponds to row r in table 1. The component factor is 1 and the multiple is 98.

Step 3

Component number	Applicable Row Table 1	Component Factor (Cp)	% in mixture	Multiple (Cp x % )
1	d	25,000	2	50,000
2	r	1	98	98
Sp				50,098

Sp = 50,098

Referring to table 2, the Sp ≥ 25,000, the mixture is therefore pollution category X.