16.1 The following can be used as guidance in
interpreting paragraphs 1 and 2 of the stacking test:
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For a 6-high stacking of 20-ton (20,320
kg/44,800 lb) containers the mass on the bottom container would be
5 x 20 tons (20,320 kg/ 44,800 lb), i.e. 100 tons (101,600 kg/224,000
lb). Thus, in the case of a 20-ton container with 6-high stacking
capability the plate should indicate: ALLOWABLE STACKING MASS FOR
1.8g: 101,600 kg/ 224,000 lb.
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16.2 The following may be useful guidance for
determining allowable stacking mass:
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The allowable stacking mass for
1.8g may be calculated by assuming a unifonn stack loading
on the cornerpost. The stacking test load applied to one corner of
the container shall be multiplied by the factor and the result expressed in appropriate units.
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16.3 The following is a useful example of how
the allowable stacking mass could be varied, as prescribed in paragraph
1 of the stacking test:
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If on a particular journey the
maximum vertical acceleration on a container can be reliably and effectively
limited to 1.2g, the allowable stacking mass permitted
for that journey would be the allowable stacking mass stamped on the
plate multiplied by the ratio of l.8 to 1.2 (i.e. allowable stacking
mass on the plate x = stacking mass permitted for the journey).
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